
Posted: Sun Feb 27, 2005 1:52 am
I'm confused by your concept of diagonal!
I do not think it means using your camera, or taking a picture on a diagonal plane.
But when given for any lens, set at infinity, and focused on the camera's film plane, and viewing glass size. Or whatever film size you are using. A lens projects a circular image at the film plane, the film used is a square or rectangular masked area within this image circle, or the covering power of a lens, focused apon the film, or expressed as the maximum film size that can be used with the lens, the diameter of the circle of good definition, or angle of coverage. With the film size area, inscribed within this area, the diagonal being the diameter of good definition, and should be larger than the diagonal of the film mask size, allowing for more movement, or croping with the view camera.
So the width times height squared, where width=5, squared is 25, and height=4, squared is 16.
Added , 25+16= 41 which is the diagonal squared (or hypotenuse) and by finding the sq. root of 41= the length of the diagonal, being, 6.4031242 ( in this case inches)
Oh! Yeah, I almost forgot! Could you give a link for your spreadsheet, saved as a PDF files for us Macintosh users, either posted here or on your web page.
Thanks!
_________________
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<font size=-1>[ This Message was edited by: Tiltall ED on 2005-02-26 17:57 ]</font>